Probabiliy formula of mutualy free events
P(A∩B) = P(A) x P(B)
Information :
P(AnB) = Probability occurrence A and occurrence B
P(A) = Probability occurrence A
P(B) = Probability occurrence B
Probabiliy example of mutualy free events
On throwing a dice at once. A is the incident appearance the dice numbers 3 on the first dice and B is the incident appearance the dice number 5 of second dice. so what is the probability of issuing dice number 3 on the first dice and the dice number 5 on the second dice?
Resolution :
S = {(1, 1), (1, 2), (1, 3),..., (6, 6)}
n(S) = 36
A = {(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)}
n(A) = 6
P(A) = n(A)/n(S)
P(A) = 6/36
P(A) = 1/6
B = {(1, 5), (2, 5), (3, 5), (4, 5), (5, 5), (5, 6)}
n(B) = 6
P(B) = n(B)/n(S)
P(B) = 6/36
P(B) = 1/6
P(A∩B) = P(A) x P(B)
P(A∩B) = (1/6) x (1/6)
P(A∩B) = 1/36
P(A∩B) = 0.028
So the probability of issuing dice number 3 on the first dice and the dice number 5 on second dice is 0.028.
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Reference :
- The mathematics book of the high school class XI IPA program
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